A 3 M solution has how many moles per liter?
1. A 3 M solution has how many moles per liter?
Answer:
A 3 M solution has 3 moles of solute per litre.
2. Describe a bottle that contains 0.95 moles of hydrogen peroxide per liter of solution?
Answer:
Describe a bottle that contains 0.95 moles of hydrogen peroxide per liter of solution?
Answer:
yfufkgicswogu ydtxljohgthhfkejhw wijwhuwgdhhd
Explanation:
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3. Calculate the concentration in grams per liter of a 450.0 mL solution containing 0.0762 moles of iodine.
Answer:
Criveu: moles of NaCI=0.006
volume of solution=100ml
to find: molarity of the solution
molarity=number of moles
______________
volume of solution
=0.006 multiply ✖️ 1000
___________________ =0.006M
100ml
therefore, molarity of the solution is 0.06M.
Explanation:
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4. A sulfuric acid solution containing 571.6 g of H2SO4 per liter of solution has a density of 1.329 g/cm3. Calculate the mass percentage, mole fraction, molality, and molarity of H2SO4 in the solution. Given: Mass H2SO4 = 571.6 g Volume of Solution = 1 L Density of solution = 1.329 g/cm3 = 1.329 g/mL Required: a)Mass % b)Mole fraction c)Molality d)Molarity
Solution (a)
Step 1: Calculate the mass of solution.
[tex]\text{mass of solution = density of solution × volume of solution}[/tex]
[tex]\text{mass of solution = 1.329 g/m L × 1000 m L}[/tex]
[tex]\text{mass of solution = 1329 g}[/tex]
Step 2: Calculate the mass percent.
[tex]\text{mass percent} = \frac{\text{mass}_{H₂SO₄}}{\text{mass of solution}} × 100[/tex]
[tex]\text{mass percent} = \frac{\text{571.6 g}}{\text{1329 g}} × 100[/tex]
[tex]\boxed{\text{mass percent = 43.01\%}}[/tex]
Solution (b)
Step 1: Calculate the mass of water.
[tex]\text{mass}_{water} = \text{mass of solution} - \text{mass}_{H₂SO₄}[/tex]
[tex]\text{mass}_{water} = \text{1329 g} - \text{571.6 g}[/tex]
[tex]\text{mass}_{water} = \text{757.4 g}[/tex]
Step 2: Calculate the molar mass of H₂SO₄ and water.
For H₂SO₄
molar mass = (1.008 g/mol × 2) + (32.07 g/mol × 1) + (16.00 g/mol × 4)
molar mass = 98.09 g/mol
For water
molar mass = (1.008 g/mol × 2) + (16.00 g/mol × 1)
molar mass = 18.02 g/mol
Step 3: Calculate the number of moles of H₂SO₄ and water.
For H₂SO₄
[tex]n_{H₂SO₄} = \text{571.6 g H₂SO₄} × \frac{\text{1 mol H₂SO₄}}{\text{98.09 g H₂SO₄}}[/tex]
[tex]n_{H₂SO₄} = \text{5.827 mol}[/tex]
For water
[tex]n_{water} = \text{757.4 g water} × \frac{\text{1 mol water}}{\text{18.02 g water}}[/tex]
[tex]n_{water} = \text{42.03 mol}[/tex]
Step 4: Calculate the mole fraction of H₂SO₄.
[tex]X_{H₂SO₄} = \frac{n_{H₂SO₄}}{n_{H₂SO₄} \: + \: n_{water}}[/tex]
[tex]X_{H₂SO₄} = \frac{\text{5.827 mol}}{\text{5.827 mol + 42.03 mol}}[/tex]
[tex]\boxed{X_{H₂SO₄} = 0.1218}[/tex]
Solution (c)
[tex]\text{molality} = \frac{n_{H₂SO₄}}{\text{mass}_{water} \: \text{(kg)}}[/tex]
[tex]\text{molality} = \frac{\text{5.827 mol}}{\text{0.7574 kg}}[/tex]
[tex]\boxed{\text{molality} = \text{7.693 m}}[/tex]
Solution (d)
[tex]\text{molarity} = \frac{n_{H₂SO₄}}{\text{volume of solution (L)}}[/tex]
[tex]\text{molarity} = \frac{\text{5.827 mol}}{\text{1 L}}[/tex]
[tex]\boxed{\text{molarity} = \text{5.827 M}}[/tex]
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5. A 10-liter solution contains 10-moles of hydrogen ions . determine whether the solution is acidic ,neutral or basic.
Answer:
if the[H+]=10^-8M then poH=
-log 10^-8 pH=8.00pH%3E
6. HOW MANY MOLES OF H2 S04 ARE PRESENT IN 1.63 LITERS OF A 0.954 M SOLUTIONS?
Answer:
1.56 mol. H2SO4
Explanation:
hope its helpp
7. There are ways on how to express the concentration of a solution, one of which is mole fraction, which of the following are needed in order to calculate the mole fraction? A. The moles of solute present in the solution. B. The volume of solution (in liters) containing the solute. C. The volume of solution (in liters) containing the solute. D. The number of moles of each component present in the solution.
A
To calculate mole fraction of solute you first calculate the moles of the solute and then you divide that by the total number of moles of solute and solvent.
8. What is the total number of moles of solute in 0.805 liters of a 3.91 M solution of NaCl?
Explanation:
To calculate the total number of moles of solute in a solution, we need to use the formula:
moles of solute = concentration (in M) x volume (in liters)
In this case, the concentration of the NaCl solution is 3.91 M, and the volume is 0.805 liters. So we can plug these values into the formula to get:
moles of solute = 3.91 M x 0.805 L
moles of solute = 3.14855 mol
Therefore, the total number of moles of solute in 0.805 liters of a 3.91 M solution of NaCl is approximately 3.14855 mol.#pabrainliest
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9. 10. I have two solutions. In the first solution, 1.0 moles of sodium chloride is dissolved tomake 1.0 liters of solution. In the second one, 1.0 moles of sodium chloride is added to 1.0liters of water. Is the molarity of each solution the same? Explain your answer.
Answer:
sorry idont know what is answer sorry
10. . What does solubility refer to? a. size of the particles that make up a substance, b. grams of solute per 100 g of solvent. c. number of moles of solvent dissolved per liter of solution. d. concentration of a solute that is dissolved in a solvent.
Answer:
letter D.concentration of a solute that is dissolved in a solvent.
Explanation:
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11. calculate the molarity of 0.060 moles of nahco3 in 1.5 liters of solution
Answer:
the answer is 0.04 molar
0.060÷1.5=0.04
12. What does solubility refer to? A. size of the particles that make up a substances. B. grams of solute per 100 g of solvent. C. number of moles of solvent dissolved per liter of solution. D. concentration of a solute that is dissol ed in a solvent.
Answer:
B. poSana po makatulong13. 1.What is the molarity of a 0.30 Liter Solution Containing 0.50 Moles of NACL? 2.Calculate the molarity of 0.289 Moles of FECL3 Dissolved in 120 ML of solution? 3.If a 0.075 Liter solution Contains 0.0877 Moles of Cuco.What is the molarity? 4.How many Moles of NACL are Present in 600 ml of a 1.55M NACL Solution? MY SOLUTION
Answer:
what is the molarity of a0.30 liter solution cotaining 0.50 moles of nacl
14. What is the molarity of a solution containing 0.16 moles of NaCl in 2.6 liters?
Answer:
0.1M
Explanation:
0.16
----
2.6
=0.06
Or 0.1
15. There are ways on how to express the concentration of a solution, one of which is mole fraction, which of the following are needed in order to calculate the mole fraction? A. The moles of solute present in the solution. B. The volume of solution (in liters) containing the solute. C. The volume of solution (in liters) containing the solute. D. The number of moles of each component present in the solution.
Answer:
C. The volume of solution (in liters) containing the solute.
Explanation:
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16. 3. A 1-liter solution contains 10-8 moles of hydrogen ions. Determine whether the solution is acidic, neutral, or basic.
Answer:
If the [H+] = 10^-8M
Then poH = - log 10^-8
pH = 8.00
pH > 7.00
solution is basic
17. A 2 l sulfuric acid solution containing 320 g of h2so4 per liter of solution has a density of 1.329 g/ ml. what is the mole fraction of the solvent in the solution
Explanation:
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18. what is the molarity of a solution containing 0.96 moles of NaCl in 3.5 liters of solution?
Answer:
0.96 moles / 3.5 liters = 48/175 or 0.2742857143
Explanation:
Molarity = Moles/Volume
19. A 1-liter solution contains 10^-8 moles of hydrogen ions. determine whether the solution is acidic, neutral, or basic
Answer:
the solution is basic since pH=8
20. What is the molarity of a solution that has 2.3 moles of sodium chloride in 0.45 liters of solution?
Answer:
0. liters 45 po
Explanation:
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21. what is the molarity of a solution containing 0.32 moles of NaCl in 3.4 liters?
Answer:
0.094 molarity
In 3.4 liters of salt solution containing 0.32 mole of sodium chloride -- table salt -- you can determine molarity by dividing 3.4 into 0.32, which yields 0.094 molarity, abbreviated as M
22. Witch refers to the number of moles solute presnt in one liter of solution A.molarityB.mass number C.atomatic numberD.isotopes
Answer:
1.molarity
Explanation:
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Answer:
Molarity
Molarity (M) indicates the number of moles of solute per liter of solution (moles/Liter) and is one of the most common units used to measure the concentration of a solution. Molarity can be used to calculate the volume of solvent or the amount of solute.
23. What is the molarity of a solution of NaOH if there are 4 moles of NaOH dissolved water to make 1 liter of solution?
Molarity (M)Discussion:
Molarity is one of the commonly used units in chemistry. Molarity is defined as the number of moles of solute per liter of solution --- that is,
[tex]\boxed{\text{molarity} = \frac{\text{moles of solute}}{\text{volume of solution (L)}}}[/tex]
For example, a 1.46 [tex]M[/tex] glucose solution contains 1.46 mol of the solute (glucose) in 1 L of the solution. Of course, we do not always work with solution volumes of 1 L. Thus, a 500-mL solution containing 0.730 mol of glucose also has a concentration of 1.46 [tex]M.[/tex]
[tex]\\[/tex]
Problem:What is the molarity of a solution of NaOH if there are 4 moles of NaOH dissolved water to make 1 liter of solution?
Given:[tex]\text{moles of solute = 4 mol}[/tex]
[tex]\text{volume of solution = 1 L}[/tex]
[tex]\text{solute = NaOH}[/tex]
Required:[tex]\text{molarity}[/tex]
Solution:[tex]\text{molarity} = \frac{\text{moles of solute}}{\text{volume of solution (L)}}[/tex]
[tex]\text{molarity} = \frac{\text{4 mol}}{\text{1 L}}[/tex]
[tex]\boxed{\text{molarity} = 4 \: M}[/tex]
[tex]\\[/tex]
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24. what is the molarity of 5 liter solution that contains 10 moles of NaCl?
Molarity = moles of solute/ Liter of solution.
the value of your mole and volume is given, just substitute it to the equation and you will obtain your Molarity.
25. pasagot po pls2. What is the molarity of the prepared solution? (Hint: mass = 4.2 grams; : molar mass = 93.886 g/mol;v of solution = 1L = ; Formula Molarity = moles of solute / Liter of solution ; moles of solute = = mass/ molar mass )
Answer:HINDI KO RIN ALAM
Explanation:
26. How many liters are in a 0.115 M solution containing 1.55 moles of dissolved KBr?
Solution:
[tex]\text{molarity} = \frac{\text{moles of solute}}{\text{volume of solution (in L)}}[/tex]
[tex]\text{volume of solution (in L)} = \frac{\text{moles of solute}}{\text{molarity}}[/tex]
[tex]\text{volume of solution (in L)} = \frac{\text{1.55 mol}}{\text{0.115 M}}[/tex]
[tex]\boxed{\text{volume of solution (in L) = 13.48 L}}[/tex]
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27. What is the volume of solution needed to prepare 5 molar solution containing of 160 grams of Sodium Hydroxide (NaOH). Na = 23g/mole O= 16g/mole H= 1g/mole A. 0.8 liter B. 1 liter C. 1.8 liters D. 8liters
Answer:
D. 8 liters
Explanation:
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28. ______is the concertration of a solution expressed as the number of moles of solute dissolved in each liter of solution
Answer:
MolarityExplanation:
Molarity tells us the number of moles of solute in exactly one liter of a solution. (Note that molarity is spelled with an "r" and is represented by a capital M.) We need two pieces of information to calculate the molarity of a solute in a solution: The moles of solute present in the solution.
29. What is the molarity of a 0.30 liter solution containing 0.50 moles of nacl?
Answer:
1.67 M
Step-by-step explanation:
Calculating Molarity of a solution
Molarity or the molar concentration is the amount of a substance in moles present in a volume of solution. The molarity can be calculated by dividing the moles of solute by the total volume of the solution accounting for the volume of solute and volume of solvent. The formula for molarity is:
M = [tex]\frac{moles of solute}{volume of the solution (Liters)}[/tex]
In this problem, our solute is the 0.50 moles of NaCl and 0.30 L solution.
Substitute the given values to the equation and solve for the Molarity.
M = [tex]\frac{moles of solute}{volume of the solution (Liters)}[/tex]
M = [tex]\frac{0.50 moles of NaCl}{0.30 Litersof solution}[/tex]
M = 1.67 M
Therefore, the molarity of the solution is 1.67M.
To learn more about molarity, click the link below:
brainly.ph/question/1634511
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30. What is the molarity of a solution that contains 4 moles of solute in 2 liters of solution?
Answer:
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